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Post by nighthawk on Feb 16, 2006 6:21:11 GMT -5
:-/Hi Everyone,
Could someone explain the principle of overrev to me?
From my sports car racing days; if you had a redline of 7200RPM and exceeded it by missing a shift or whatever, the engine would go "Bang" and your Visa bill just got a lot higher! ;D If I run a shifter engine to a redline of 13.1, how do I get that extra 600rpm or "overrev" at the end of a straight? Confused!
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glen
Junior Poster
Posts: 40
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Post by glen on Feb 16, 2006 10:00:18 GMT -5
Well, I'm no expert here, but see if this seems logical. The first difference is that you are running a single cylinder 2 stroke instead of a multi-cylinder 4 stroke, so there are lots less moving parts, and it's much simpler to balance for high speeds. The second thing is that two stroke power bands don't tend to be very wide, therefore power can drop off quickly if you rev past the rpm where all the magic that makes a 2 stroke work at, but you can still be within the mechanical limits of the rotating assembly. So essentially you are "overreving" past the powerband not the actual engine componnents.
Glen
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Post by nighthawk on Feb 16, 2006 19:59:59 GMT -5
Thanks Glen,
Yes, your explanation actually makes sense. ;D So, if I am threshold braking then downshifting before turn-in, I can actually exceed redline somewhat because of the over-rev? If I apply the brakes just short of lockup I should be down under redline when I start my downshifts but it looks like I might have a bit of a mechanical safety margin just in case. Thanks for the help. It's hard sometimes to change your thinking from 4-stroke multi-cylinder to 2-stroke single cylinder but my dumb questions and help from people like you are making the steep learning curve a little easier. ;D
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